Question

The population of a town increases by 8 percent annually. if the present population is 54000 what was it a year ago

Answer 1

5000

Explanation:

The relationship between population and a yearly growth rate rate is given by:

P(t) = Pi*(1+R)^t

where Pi is the initial population, P(t) is the population at year t, where t=0 for the initial year.

In this case, P(1) = 5400, R is 0.08 (8%), and t = 1.

5400 = Pi*(1+0.08)^1

pi = (5400)/(1.08)

pi = 5000

Answer 2

58696

Explanation:

okay so 54000 has occurred AFTER the 8% has been added. So there is a number, let's call it "a" that when multiplied by 92% has resulted in 54000. So we get this:

a x 0.92 = 54000

a = 54000/0.92

a = 58695.65 or 58696

Now just to confirm the answer:

58696 x 0.08 = 4695.68

And subtract that:

58696 - 4695.68 = 54000.32 (54000)

which confirms the answer