Question

Given that f(x)= (x^2+1)^5 , find f ' (1)

Answer 1

f(x) = (x² + 1)⁵

f'(x) = 5(x² + 1)⁴(2x)

f'(1) = 5(1² + 1)⁴(2(1)) = 5(2⁴)(2) = 160