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Given that f(x)= (x^2+1)^5 , find f ' (1)

User Roadmaster
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Answer:

f(x) = (x² + 1)⁵

f'(x) = 5(x² + 1)⁴(2x)

f'(1) = 5(1² + 1)⁴(2(1)) = 5(2⁴)(2) = 160

User Yu Chia Wu
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