Question

John rolls a pair of fair number cubes both numbered from one to six. what is the probability that one number cube will show a 1 and the other will show a 6?

Answer 1

Here we go ~

Total number of possibilities out there are :

`\qquad\displaystyle \tt \rightarrow \: 6 * 6 = 36`

And for one of the cube to show 1 and the other to show 6, there are :

`\qquad\displaystyle \tt \rightarrow \: 2 \: \: possible \: \: outcomes`

that are : (1 , 6) and (6 , 1)

So, probability of getting the desired outcome will be ~

`\qquad\displaystyle \tt \rightarrow \: (2)/(36)`

After simplification :

`\qquad\displaystyle \tt \rightarrow \: (1)/(18)`