Question

If 1.25 L of acetylene at 0.747 atm can be made from 5.00 g of limestone, what is the temperature of the gas in kelvin?

Answer 1

227.47 K

Step-by-step explanation:

It mentions Volume, Pressure Grams (to Moles) and Temperature

therefore we need to use the formula PV = nRT

P is pressure v is volume = n is moles r is universal gas constant (0.0821 always) t is temperature

Convert grams to moles to fit formula

5g / grams of CaCO3 (limestone)

5g / 100.09g CaCO3

= 0.05 mol

Now plug all into formula

PV = nRT

(0.747atm) (1.25L) = (0.05mol) (0.0821) ( T )

0.93375 = (0.004105) ( T )

/0.004105 on both sides

227.47 K (Kelvin)