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Pls help with this equation question. thank you

Pls help with this equation question. thank you-example-1
User Stanton
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1 Answer

1 vote

Answer:

  • 7
  • 4

Explanation:

You want to know the values of 'a' and 'b' in the equation ...

2(a -6x) +b(5x -1) = 2(4x +5)

Simplify

Using the distributive property to eliminate parentheses we have ...

2a -12x +5bx -b = 8x +10

Subtracting the right side from both sides gives ...

-12x +5bx -8x +2a -b -10 = 0

(-20 +5b)x +(2a -b -10) = 0

Coefficients

Equating coefficients gives us equations in 'a' and 'b':

-20 +5b = 0 ⇒ b = 20/5 = 4 . . . . . . coefficient of x

2a -b -10 = 0 ⇒ 2a -4 -10 = 0 ⇒ a = 14/2 = 7 . . . . . . constant term

The equation with the right numbers in the boxes is ...


2(\boxed{7}-6x)+\boxed{4}(5x -1) = 2(4x +5)

<95141404393>

User Mark McKelvy
by
8.0k points

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