Answer:
The sum of the digits of a three-digit number is 6. The hundreds digit is twice the units digit,
and the tens digit equals the sum of the other two. Find the number.
Let the digits be x , y ,z
x hundred's place
y ten's place
z unit's place
The number will be XYZ
The sum of the digits of a three-digit number is 6
x+y+z=6
The hundreds digit is twice the units digit,
x = 2z
the tens digit equals the sum of the other two
y=x+Z
x+y+z=6 ( substitute y)
x+x+z+z =6
2x+2z=6
But x =2z ( substitute x=2z)
2(2z)+2z=6
6z=6
z=1
x=2z
x= 2*1 =2
Y=x+z
y = 1+2 =3
The number is 231