Question

Can u answer the screenshot

Answer 1

Hello!

Answer:

`\Large \boxed{\sf A =-6}\\\Large \boxed{\sf B =-3}\\\Large \boxed{\sf C =2}`

Explanation:

◼◼For A:

◼ Replace x by (-3):

`\sf y = (-3)^(2) + 4* (-3) -3`

◼ Simplify the equation:

`\boxed{\sf y = -6}`

◼◼For B:

◼ Replace x by 0:

`\sf y = 0^(2) + 4* 0 -3`

◼ Simplify the equation:

`\boxed{ \sf y = -3}`

◼◼For C:

◼ Replace x by 1:

`\sf y = 1^(2) + 4* 1 -3`

◼ Simplify the equation:

`\boxed{\sf y = 2}`

Answer 2

See below!

Explanation:

Given equation:

y = x² + 4x - 3

`\rule[225]{225}{2}`

Put x = -3 in the above equation.

y = (-3)² + 4(-3) - 3

y = 9 - 12 - 3

y = -3 - 3

y = -6

So,

A = -6

`\rule[225]{225}{2}`

Now,

Put x = 0

y = (0)² + 4(0) - 3

y = 0 + 0 - 3

y = -3

So,

B = -3

`\rule[225]{225}{2}`

Put x = 1

y = (1)² + 4(1) - 3

y = 1 + 4 - 3

y = 5 - 3

y = 2

So,

C = 2

`\rule[225]{225}{2}`