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a 6.5 kg object oscillates on a spring with an amplitude of 94.8 cm with a maximum acceleration of 5.2 m/s 2 . find the total energy. answer in units of j.

User AXqd
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Answer:

a = -ω^2 A maximum acceleration

ω^2 = k / m angular frequency

E = 1/2 k A^2 maximum kinetic energy

a = k * A / m rewriting first equation

k = a * m / A = 5.2 * 6.5 / .948 = 35.6

E = 1/2 * 35.6 * .948^2 = 16.0 Joules

User Mitesh Rathod
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