Answer:
0.0225 moles
Step-by-step explanation:
iron (iii) oxide has a chemical formula of Fe2O3.
This means that for every mole of iron 3 oxide formed, 2 moles of Fe and 3 moles of oxygen is needed.
By stoichiometry we know that moles=mass ÷ Mr
Ar of Fe is approximately 56
Ar of O is approximately 16
Mr of Fe2O3 is 56(2) + 3(16) = 160.
moles of fe2o3= 1.80÷160 = 0.01125 mol
Since 2 moles of Fe is needed for the synthesis,
moles of Fe needed is 0.01125 x 2 =0.0225 moles