Answer and Step-by-step explanation:
Let's break down the information given:A and B had the same number of coins. A had 8 twenty-cent coins, while B had 20 twenty-cent coins. This means that the total number of coins for A and B is the same.Let's denote the number of coins for A and B as "x." Therefore, A had 8 twenty-cent coins and B had 20 twenty-cent coins, so the remaining coins for A and B must be fifty-cent coins.Since A and B had the same number of coins, we can set up the equation:8 + (x - 8) = 20Simplifying the equation, we get:x - 8 = 20 - 8x - 8 = 12Adding 8 to both sides:x = 12 + 8x = 20Therefore, A and B each had a total of 20 coins.Now, we know that C had only fifty-cent coins. Since A, B, and C had the same number of coins, C also had 20 coins.To summarize:A had 20 coins, consisting of 8 twenty-cent coins and 12 fifty-cent coins.B had 20 coins, consisting of 20 twenty-cent coins and 0 fifty-cent coins.C had 20 coins, consisting of 20 fifty-cent coins.