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Last question. Finally. Please help one last time, PLEASE!

Last question. Finally. Please help one last time, PLEASE!-example-1
User RasmusGP
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2 Answers

4 votes

Answer:

2. m∡1=80°

4. m∡2=100°

Only for specific triangle.

Explanation:

Statement (Reason in bracket)

1. m∡1+m∡A+m∡B=180°(The interior angle measures of a triangle sum to 180)

m∡1+60°+40°=180°

m∡1=180°-60°-40°

2. m∡1=80° (substituting value of m∡1)

3. m∡1+m∡2=180° (The angle measures of a linear pair sum to 180°)

80°+ m∡2=180°

m∡2=180°-80°

m∡2=100°

4. m∡2=100° (Substitute and solve for m∡2)

5. m∡A+m∡B = 100°( Add given angle measures)

6. m∡2=m∡A+ m∡C (Substitution)

Therefore, we proved the conclusion that it is true for this specific triangle only, since the angles of other triangles could be formed in a differently.

Therefore, we proof the conclusion for only for specific triangle.


\boxed{\tt Good\: Luck}

User Djaszczurowski
by
7.9k points
3 votes

Answer:


\textsf{Statement\;2:} \quad m \angle 1 =\boxed{80^(\circ)}


\textsf{Statement\;4:} \quad m \angle 2 =\boxed{100^(\circ)}


\Large\textcircled{\small B}}\;\;\sf Only\; for\; this\; specific \;triangle

Explanation:

Statement 2

As the interior angles of a triangle sum to 180°, then for the given triangle we can say that:


m \angle 1 + m \angle A + m \angle C = 180^(\circ)

From inspection of the given triangle, m∠A = 60° and m∠C = 40°.

Substitute these angles into the equation from statement 1 and solve for m∠1:


m \angle 1 + 60^(\circ) + 40^(\circ) = 180^(\circ)


m \angle 1 + 100^(\circ) = 180^(\circ)


m \angle 1 + 100^(\circ)-100^(\circ) = 180^(\circ)-100^(\circ)


m \angle 1 =80^(\circ)

Therefore, the measure of angle 1 is 80°.


\hrulefill

Statement 4

A linear pair is two angles which when combined together form a straight line. Therefore, the angle measures of a linear pair sum to 180°.

As ∠1 and ∠2 form a linear pair, we can say that:


m \angle 1 + m \angle 2= 180^(\circ)

Substitute the found value of m∠1 and solve for m∠2:


80^(\circ) + m \angle 2= 180^(\circ)


80^(\circ) + m \angle 2-80^(\circ)= 180^(\circ)-80^(\circ)


m \angle 2= 100^(\circ)

Therefore, the measure of angle 2 is 100°.


\hrulefill

The conclusion is only true for this specific triangle, since the angles of other triangles could be labelled in a different way.

For example, ∠A in this triangle could be labelled as ∠B in another triangle, which would mean that this specific conclusion would not hold true.

User Fareevar
by
7.9k points

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