Question

What is a pointslope equation of the line with slope -12 that goes through the point (5, 3) ?

Answer 1

`\textsf{D)} \quad y-3=-12(x-5)`

Explanation:

The point-slope form of a linear equation is:

`y-y_1=m(x-x_1)`

where:

• m is the slope.
• (x₁, y₁) is a point on the line.

Given values:

• m = -12
• (x₁, y₁) = (5, 3)

Substitute the given slope and point into the formula to write a point-slope equation of the line:

`\large\boxed{y-3=-12(x-5)}`