Final answer:
To calculate the average binding energy per nucleon, we divide the total binding energy by the total number of nucleons. For 2656Fe, the average binding energy per nucleon is 2352.29 MeV, and for 92238U, it is 19.4 MeV.
Step-by-step explanation:
To calculate the average binding energy per nucleon, we divide the total binding energy of the nucleus by the total number of nucleons in the nucleus. We can use the equation BE = (Am)c², where Am is the mass defect. In the case of 26Fe, we need to find the mass defect and then divide the binding energy by the total number of nucleons. We can use the information from Example 21.3, which states that the binding energy per nucleon for 56Fe is 493.9 MeV. Therefore, the average binding energy per nucleon for 2656Fe would be:
(2656/56) * 493.9 MeV = 2352.29 MeV/nucleon (rounded to four significant figures).
Similarly, for 92U238, we can use the information from Example 15.4.3, which states that the binding energy per nucleon for 235U is about 7.6 MeV. Therefore, the average binding energy per nucleon for 92238U would be:
(238/92) * 7.6 MeV = 19.4 MeV/nucleon (rounded to four significant figures).