Question

I need someone to help write this code is about converting octals number to decimal

using MIPS assembly language also using MARS 4.5

output:

Enter number in octal=323

octal=323

decimal=211

Answer 1

The student needs to write MIPS assembly code to convert octal numbers to decimal using MARS 4.5. An example code snippet can guide the student through the process, which entails multiplying each octal digit by powers of 8 based on their positions.

Step-by-step explanation:

The student has asked for assistance in writing MIPS assembly language code to convert an octal number to its decimal equivalent using the MARS 4.5 simulator. The code should prompt the user to enter an octal number and then output both the original octal number and the converted decimal number. The process involves reading the octal number as a string, converting it to an integer, and then calculating the decimal value by multiplying each digit by the power of 8 corresponding to its position.

Example Code to Convert Octal to Decimal in MIPS

Below is an example code snippet for the conversion:

.data
prompt: .asciiz "Enter number in octal="
.text
.globl main
main:
li $v0, 4 # syscall for print string
la $a0, prompt # load address of prompt into $a0
syscall # print prompt
#... More code for input and conversion ...#
# Output the result

Conversion Logic Explanation

To perform the conversion, iterate through the characters of the string, convert each character from an octal digit to its integer equivalent, and accumulate the result in a running sum where each digit is multiplied by 8^n (where n is the position of the digit from right to left, starting at 0).

Answer 2

To convert an octal number to decimal in MIPS assembly language using MARS 4.5, you need to use a loop to process each digit of the octal number. The code snippet provided demonstrates how to convert an octal number to decimal and print both the original octal number and the decimal equivalent.

Step-by-step explanation:

To convert an octal number to decimal in the MIPS assembly language, you can use a loop to process each digit of the octal number. Here's an example code snippet:

.data

prompt: .asciiz "Enter the number in octal: "

octal: .word 0

decimal: .word 0

.text

main:

# Print a prompt message

li $v0, 4

la $a0, prompt

syscall

# Read the octal number from the user

li $v0, 5

syscall

move $t0, $v0

# Convert octal to decimal

li $t2, 1

sll $t1, $t0, 2

sum_loop:

rem $t3, $t1, 10

mul $t3, $t3, $t2

add $t0, $t0, $t3

div $t1, $t1, 10

mul $t2, $t2, 8

bnez $t1, sum_loop

# Print original and decimal values

li $v0, 4

la $a0, octal

syscall

li $v0, 1

move $a0, $t0

syscall

li $v0, 4

la $a0, decimal

syscall

li $v0, 1

lw $a0, 0($t0) syscall

# Exit program

li $v0, 10

syscall