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Two buses leave towns 750 miles apart at the same time and travel toward each other. One bus travels 11(mi)/(h) faster than the other. If they meet in 6 hours, what is the rate of each bus?

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Answer: Faster bus=68mph, Slower bus=57mph

Step-by-step explanation:

In this type of question, we can create an equation that can help us determine the speed. First we have to note that buses are going towards each other which means they are working together to cover up the distance of 750mi, now lets say that the slower bus' speed is x, this would mean that the faster bus' speed is x+11, and we know that the whole distance is 750mi, and we also should note that they met after 6 hours, so by this details we can make up the equation, 6(x)+6(x+11)=750, now we can solve for x, lets simplify the equation, 6x+6x+66=750,--->12x+66=750, now minus 66 on both sides which will give us 12x=684, now we divide both sides by 12 which will give us, x=57, now the x is the speed of the slower bus, if we want to now get the speed of the faster bus we just add 11, which will give us 68.

Hope it helped

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