Final answer:
The equations representing the boundaries of the light emitted by the table lamp in the shape of a hyperbola are y = (5/12)x and y = -(5/12)x.
Step-by-step explanation:
The equation of the hyperbola is given by 25x^2 - 144y^2 + 3600 = 0. To find the boundaries of the light, we need to solve for y in terms of x. Let's solve the given equation for y:
25x^2 - 144y^2 + 3600 = 0
-144y^2 = -25x^2 + 3600
y^2 = (25/144)x^2 - 25
y = ±sqrt((25/144)x^2 - 25)
So, the equations representing the boundaries of the light are y = (5/12)x and y = -(5/12)x.