Final answer:
The inverse of the matrix [[3,-4],[5,-8]] exists and is computed by first calculating its determinant (which is not zero) and then applying the formula for the inverse of a 2x2 matrix. The result is the matrix [[2, -1], [1.25, -0.75]].
Step-by-step explanation:
To find the inverse of a 2x2 matrix, you can use the formula:
If the given matrix A is:
A = [[a, b], [c, d]]
The inverse of matrix A, denoted A-1, is given by:
A-1 = (1/det(A)) * [[d, -b], [-c, a]], where det(A) is the determinant of matrix A.
First, we calculate the determinant:
det(A) = (3)(-8) - (-4)(5) = -24 - (-20) = -24 + 20 = -4
Since the determinant is not zero, the inverse exists. Now we can calculate the inverse using the formula:
A-1 = (1 / -4) * [[-8, 4], [-5, 3]]
A-1 = [[2, -1], [1.25, -0.75]]
So, the inverse of the matrix [[3,-4],[5,-8]] is [[2, -1], [1.25, -0.75]]