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You are waiting for the bus when you notice Christopher Lloyd and Michael J. Fox down the street. Iney are travelling on hoverboards at a speed of 8.9 m/s towards you with Christopher in front of Michael. The two of them seem to be doing some sort of science experiment as they are each carrying a,sound generator that is set to the same frequency. You notice that during the time when you are in between Christopher and Michael (such that Christopher is travelling away from you and Michael is travelling towards you), you hear a beat with a frequency 4.3 Hz. What is the frequency of their sound generator?

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Final answer:

To find the frequency of the sound generators carried by Christopher Lloyd and Michael J. Fox, we must apply the Doppler Effect principle. The beat frequency observed is the difference in the Doppler-shifted frequencies from each actor, and one could use the Doppler Effect equations to find the original frequency if numerical values were given.

Step-by-step explanation:

To determine the frequency of the sound generators Christopher Lloyd and Michael J. Fox are carrying, we will use the concept of the Doppler Effect. The Doppler Effect describes the change in the frequency of a wave in relation to an observer moving relative to the source of the wave.

The beat frequency is the absolute difference in frequencies produced by the sound sources as they move relative to the observer. When Christopher is moving away and Michael is moving towards you, the frequencies they produce will be shifted up and down respectively, from the original frequency due to the Doppler Effect. Assuming both are traveling at the same speed and considering the speed of sound in air to be approximately 343 m/s, the observed beat frequency when you are exactly between them is 4.3 Hz, which is the difference between the shifted frequencies observed from each actor. Using the formula for the Doppler Effect:

f' = f (v + vo) / (v + vs)

For the sound generator moving towards you (Michael), v is the speed of sound, vo is the speed of the observer (0 m/s since you're stationary), and vs is negative because the source is moving toward the observer:

f' = f (343 m/s) / (343 m/s - 8.9 m/s)

For the sound generator moving away from you (Christopher), vs is positive:

f'' = f (343 m/s) / (343 m/s + 8.9 m/s)

So, the beat frequency (fb) is:

fb = |f' - f''| = 4.3 Hz

We can solve these simultaneous equations to find the original frequency (f).

Given the complexity of solving these equations involving Doppler Effect corrections and the observed beat frequency without specific numerical values for the original frequency, we are unable to provide the exact frequency here. However, this approach would allow you to calculate it if numerical values were given or could be derived from additional context.

User Zjmiller
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The frequency of their sound generator is 17.8 Hz.

The beat frequency you hear is the difference between the frequencies of the two sound generators. Let's calculate the beat frequency step by step.

1. The beat frequency (f_beat) is given as 4.3 Hz.
2. The beat frequency is the difference between the frequencies of the two sound generators.
3. Let's assume the frequency of Christopher's sound generator is f_C and the frequency of Michael's sound generator is f_M.
4. Since Christopher is traveling away from you, the frequency you hear from Christopher is lower than the actual frequency (f_C - v_C), where v_C is Christopher's velocity.
5. Similarly, since Michael is traveling towards you, the frequency you hear from Michael is higher than the actual frequency (f_M + v_M), where v_M is Michael's velocity.
6. Therefore, the beat frequency can be calculated as (f_C - v_C) - (f_M + v_M).
7. We are given that Christopher is in front of Michael, so v_C is positive and v_M is negative.
8. Substituting the given values, we have (f_C - 8.9) - (f_M + (-8.9)) = 4.3.
9. Simplifying the equation, we get f_C - f_M = 17.8.
10. Therefore, the frequency of their sound generator (f_C or f_M) is 17.8 Hz.

User Pbristow
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