The robot's velocity relative to the platform is approximately
in the northern direction.
The total momentum of the system (robot + steel beam) remains constant as there are no external forces acting on it in space. The initial momentum is zero since both objects are motionless relative to the platform.
The mass of the robot is 125 kg, and the mass of the steel beam is 330 kg.
When the robot starts walking along the beam, its velocity relative to the beam is given as 1.65 m/s south.
Let's consider the conservation of momentum.
Initial momentum of the system = Final momentum of the system
The initial momentum is zero since both the robot and the beam are motionless relative to the platform.
The final momentum will be the sum of the momenta of the robot and the beam after the robot starts walking.
Let
be the velocity of the robot relative to the platform.
The momentum of the robot after it starts walking = Mass of the robot × Velocity of the robot relative to the platform

The momentum of the steel beam after the robot starts walking = Mass of the steel beam × Velocity of the robot relative to the beam

According to the conservation of momentum:
![\[0 = 125 \text{ kg} * V_{\text{robot}} + 330 \text{ kg} * 1.65 \text{ m/s}\]](https://img.qammunity.org/2024/formulas/physics/high-school/9iumwh4texcbegh4zpx8bleg2uhdq0lr8f.png)
Solving for \(V_{\text{robot}}\):
![\[V_{\text{robot}} = - \frac{330 \text{ kg} * 1.65 \text{ m/s}}{125 \text{ kg}}\]](https://img.qammunity.org/2024/formulas/physics/high-school/uhc92t308u5xvpc7dldmrrptsyxxr8h4io.png)
![\[V_{\text{robot}} \approx -4.356 \text{ m/s}\]](https://img.qammunity.org/2024/formulas/physics/high-school/y285axn7sa5abx6b6nr8idunscr5ixs5fh.png)
The negative sign indicates that the robot is moving in the opposite direction to the initial position of the beam relative to the platform.