Question

Which line(s) of code have a runtime or compile error:

package cop3337.exam3;
public class COP3337Exam3
public static void main(String[] args)
int[] numbers = new int[10];
try
try
2
3
for(int i=0; i< 10; i++) numbers [i] = 18 *i;
13
14
if(i%2== 1) throw new Exception("P1");
15 16
17
if(i%2==0)
throw new ArrayIndexOutOfBoundsException("P2");

18
19
20
//end for
catch(ArithmeticException e)
System.out.print(e.getMessage() + " L1"); catch(ArrayIndexOutOfBoundsException e)
System.out.print(e.getMessage()+" L2 "); catch(Exception e)
System.out.println(e.getMessage()+" L3 "); finally
throws new Exception("L4");
catch(Exception e)
33
34
35
System.out.println(e.getMessage()+" L5");
36
37
System.out.print("\\");
//end main
38
39
//end class
12, 32
15
No error in code:
29

Answer 1

The lines of code that have runtime or compile errors are:

12: The line is missing a semicolon to terminate the line.

32: The line `throws new Exception("L4");` is syntactically incorrect. The `throws` keyword is used in a method declaration to specify the exceptions that can be thrown by that method, but it is not used within a `finally` block.

Additionally, there is an error in the code logic:

15: The `throw new Exception("P1");` statement is inside the `for` loop without any condition. It will throw an exception in every iteration of the loop.

So, the lines with errors are:

12

15

32

The line 29 states that there are no errors in the code, but that is incorrect.