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Three people invest in a business. The first two invest in the ratio 2:3, and the third person invests twice as much as the other two com-

bined.The total invested is $30 million.

How much did each person invest?

User David Hunt
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1 Answer

5 votes

Answer:

$4 million, $6 million and $20 million

Step-by-step explanation:

Let's denote the amounts invested by the first person, the second person, and the third person as x, y, and z, respectively.

According to the given information:

1. The first two people invest in the ratio 2:3. This means the ratio of their investments is 2/3.

So we can write:

x/y = 2/3 ----(1)

2. The third person invests twice as much as the other two combined. The total investment of the first two people is x + y.

So we can write:

z = 2(x + y) ----(2)

3. The total investment is $30 million.

x + y + z = 30 ----(3)

To solve this system of equations, we can use substitution or elimination method.

Let's start with the substitution method:

From equation (2), we have:

x + y = z/2 ----(4)

Substitute equation (4) into equation (3):

z/2 + z = 30

Multiply both sides by 2 to get rid of the fraction:

z + 2z = 60

3z = 60

z = 60/3

z = 20

Now substitute the value of z into equation (2):

20 = 2(x + y)

10 = x + y ----(5)

We now have two equations: (1) and (5).

From equation (1):

x/y = 2/3

Rearrange it as:

3x = 2y

Substitute the value of x from equation (5) into the above equation:

3(10 - y) = 2y

30 - 3y = 2y

30 = 5y

y = 30/5

y = 6

Substitute the value of y into equation (5):

10 = x + 6

x = 10 - 6

x = 4

So, the first person invested $4 million, the second person invested $6 million, and the third person invested $20 million.

User Helium
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