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A ball that is dropped from a height of y has a kinetic energy of K right before it hits the ground. If the same ball is lifted to a height of 2y and dropped, its kinetic energy right before hitting the ground will be 2K

2
1

K
2K

K Correct Answen 2K 4K Oftpoin A ball thrown with a speed v has kinetic energy K, If the ball were instead thrown with a speed of 2v, its kinetic energy would be ×0
2

K correct Ammen 4K
2
1

K 2K

User Marcus P S
by
7.7k points

1 Answer

4 votes

The answer is 2K.

Conservation of Energy: In this scenario, we can apply the principle of conservation of energy. This principle states that energy cannot be created or destroyed, only transformed from one form to another. In this case, the ball's potential energy (due to its height) is converted into kinetic energy (energy of motion) as it falls.

Potential Energy and Height: The potential energy of an object is directly proportional to its height. When the ball is lifted to a height of 2y, its potential energy becomes twice as much as it was at height y. This is because potential energy (PE) is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Kinetic Energy at Impact: When all of the potential energy is converted into kinetic energy at the moment of impact, the ball's kinetic energy will also be twice as much as it was when dropped from height y. This means the kinetic energy will be 2K.

Therefore, the correct answer is 2K.

Complete Question:

A ball that is dropped from a height of y has a kinetic energy of K right before it hits the ground. If the same ball is lifted to a height of 2y and dropped, its kinetic energy right before hitting the ground will be

a. 4K

b.
{ }_2^1 K

c.
√(2) K

d. K

e. 2K

User AJMansfield
by
8.2k points

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