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Two particles each weigh 1.10 N. Find the magnitude of their mutual gravitational force when they are separated by a distance of 20.0 cm.

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Final Answer:

The magnitude of the mutual gravitational force between the two particles is approximately 0.0088 N.

Step-by-step explanation:

The gravitational force between two objects can be calculated using Newton's law of gravitation:
\(F = (G \cdot m_1 \cdot m_2)/(r^2)\), where G is the gravitational constant
(\(6.67 * 10^(-11) \, \text{N m}^2/\text{kg}^2\)),
\(m_1\) and \(m_2\) are the masses of the two objects, and r is the separation distance between their centers.

In this case, both particles weigh 1.10 N, and their masses m can be determined using
\(m = (w)/(g)\), where \(w\) is the weight and \(g\) is the acceleration due to gravity (approximately
\(9.8 \, \text{m/s}^2\)). Once the masses are known, the gravitational force can be calculated.

Substituting the values into the formula, we get
\(F \approx ((6.67 * 10^(-11)) \cdot (1.10) \cdot (1.10))/((0.20)^2) \approx 0.0088\) N.

User Jonny Cundall
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