Question

Two particles each weigh 1.10 N. Find the magnitude of their mutual gravitational force when they are separated by a distance of 20.0 cm.

Answer 1

The magnitude of the mutual gravitational force between the two particles is approximately 0.0088 N.

Step-by-step explanation:

The gravitational force between two objects can be calculated using Newton's law of gravitation:
`\(F = (G \cdot m_1 \cdot m_2)/(r^2)\)`, where G is the gravitational constant
`(\(6.67 * 10^(-11) \, \text{N m}^2/\text{kg}^2\)),`
`\(m_1\) and \(m_2\)` are the masses of the two objects, and r is the separation distance between their centers.

In this case, both particles weigh 1.10 N, and their masses m can be determined using
`\(m = (w)/(g)\)`, where \(w\) is the weight and \(g\) is the acceleration due to gravity (approximately
`\(9.8 \, \text{m/s}^2\)`). Once the masses are known, the gravitational force can be calculated.

Substituting the values into the formula, we get
`\(F \approx ((6.67 * 10^(-11)) \cdot (1.10) \cdot (1.10))/((0.20)^2) \approx 0.0088\)` N.