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A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift.what is the approximate volume of the tube? round to the nearest whole cubic centimeter.1,005 cm31,340 cm33,351 cm34,021 cm3

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Answer:

1,005 cm³

Explanation:

Since the tube is in a cylindrical shape, we should use the equation for finding the volume of a cylinder: V = πr²h. r is the radius of the cylinder, and h is the height.

We are given that the diameter is 8 cm, so we should divide that number in half in order to get a radius of 4 cm. Plug that value along with a height of 20 cm into the equation to solve for the volume.

  • V = πr²h
  • V = π(4 cm)²(20 cm)
  • V = 1005.3 cm³

The approximate volume of a cylindrical cardboard tube with a diameter of 8 cm and a height of 20 cm is 1,005 cm³.

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