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How many moles of (NH4)2CrO4 are there in 304.2 g of (NH4)2CrO4?

2 Answers

1 vote

Answer:

1.207 moles

Step-by-step explanation:

Hi! To solve this problem, we need to use the molar mass of (NH4)2CrO4 and the given mass to find the number of moles of (NH4)2CrO4.

The molar mass of (NH4)2CrO4 can be calculated by adding the atomic masses of all the atoms in the compound.

The atomic masses are:

  • N: 14.01 g/mol
  • H: 1.01 g/mol
  • Cr: 52.00 g/mol
  • O: 16.00 g/mol

So, the molar mass of (NH4)2CrO4 is:

(2 x 14.01 g/mol) + (8 x 1.01 g/mol) + 52.00 g/mol + (4 x 16.00 g/mol) = 252.06 g/mol

Now, we can use the given mass and the molar mass to find the number of moles of (NH4)2CrO4:

Number of moles = Mass / Molar mass

Number of moles = 304.2 g / 252.06 g/mol

Number of moles = 1.207 moles

Therefore, there are 1.207 moles of (NH4)2CrO4 in 304.2 g of (NH4)2CrO4.

User Jalakoo
by
8.6k points
3 votes

Answer:

approximately 2 moles

Explanation: molar mass of (NH4)2CrO4 is about 152 g/mol. 304 grams/152g/mol ≈ 2 moles

User The Jakester
by
8.6k points