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A source charge generates an electric field of 4286 n/c at a distance of 2.5 m. what is the magnitude of the source charge? (use k=) 1.2 �c 3.0 �c 1.2 c 3.0 c

User Pradeek
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2 Answers

5 votes

Answer:

1.2 μC

Step-by-step explanation:

We can use Coulomb's law to solve for the magnitude of the source charge. Coulomb's law states that the electric field generated by a point charge q at a distance r from the charge is given by:

E = k * (q / r^2)

where E is the electric field, k is Coulomb's constant (k = 8.99 × 10^9 N m^2 / C^2), q is the magnitude of the charge, and r is the distance from the charge.

In this problem, we are given the electric field E and the distance r, and we need to solve for q. Rearranging Coulomb's law, we get:

q = E * r^2 / k

Substituting the given values, we get:

q = (4286 N/C) * (2.5 m)^2 / (8.99 × 10^9 N m^2 / C^2) = 1.2 × 10^-6 C

Therefore, the magnitude of the source charge is 1.2 μC.

So, the answer is 1.2 μC.

User Jingnan Jia
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The answer to your question is k -12 + 14x is equal
User Florian Reisinger
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