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Find an equation of the tangent plane to the given surface at the specified point. z=yln(x),(1,4,0)

Find an equation of the tangent plane to the given surface at the specified point. z=yln(x),(1,4,0)
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Find an equation of the tangent plane to the given surface at the specified point. z=yln(x),(1,4,0)

User Darice
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The answer to your question is x= xy14 because I did this on edg and got it right by MIs huevos and the tangent plane is 13
User Raphael Castro
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