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If a=-x+2i and b=2i then find the value of the ab^3 in fully simplified form.

User Larsaars
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Answer: The value of ab^3, in fully simplified form, is 8ix - 16.

Step-by-step explanation: We enter the known values of a and b into the following formula to get the value of ab3:

a = -x + 2i b = 2i

ab^3 = (-x + 2i)(2i)^3

Let's first simplify (2i)3:

(2i)^3 = 2^3 * i^3 = 8 * (-i) = -8i

We now re-enter this value into the expression:

ab^3 = (-x + 2i)(-8i)

We employ the distributive property to further simplify this:

-8i(-x) + (-8i)(2i) = ab3

Increasing the terms by

ab^3 = 8ix + 16i^2

Since the definition of i2 is -1, we can further simplify:

ab^3 = 8ix + 16(-1)

ab^3 = 8ix - 16

As a result, ab3 has the value 8ix - 16 in fully simplified form.

User Alex Cohen
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