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How would you write the equation with a slope of 23 and a y-intercept of -3

2 Answers

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Answer:

First at all, you need to remember that y-intercept is the point where the line crosses the y-axis. In other words you need to have X=0, so your point is X=0 and Y=-3.

Second, you have the value of the slope which is 2/3.

With this information you can use the lineal equation in slope of a line form : m=(Y2 - Y1) / (X2 - X1)

Substitute the values of your point (0, -3) and the value of the slope 2/3, and rewrite the equation:

Y - (-3) / (X - 0) = 2/3

(Y + 3) / X = 2/3

Multiplying both sides of the equation by X

Y + 3 = (2/3)X, subtracting -3 in both sides of the equation you are going to have your equation base on the value of the slope and y-intercept

Y= (2/3)X - 3

User Jeff Paulsen
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6 votes

Answer: Hence, the equation of the line with slope

Step-by-step explanation: =2 and y-intercept =3 is y=2x+3

User Ed Willink
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