34.7k views
5 votes
How would you write the equation with a slope of 23 and a y-intercept of -3

2 Answers

2 votes

Answer:

First at all, you need to remember that y-intercept is the point where the line crosses the y-axis. In other words you need to have X=0, so your point is X=0 and Y=-3.

Second, you have the value of the slope which is 2/3.

With this information you can use the lineal equation in slope of a line form : m=(Y2 - Y1) / (X2 - X1)

Substitute the values of your point (0, -3) and the value of the slope 2/3, and rewrite the equation:

Y - (-3) / (X - 0) = 2/3

(Y + 3) / X = 2/3

Multiplying both sides of the equation by X

Y + 3 = (2/3)X, subtracting -3 in both sides of the equation you are going to have your equation base on the value of the slope and y-intercept

Y= (2/3)X - 3

User Jeff Paulsen
by
7.8k points
6 votes

Answer: Hence, the equation of the line with slope

Step-by-step explanation: =2 and y-intercept =3 is y=2x+3

User Ed Willink
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories