Answer:
To determine the weight of 1*10^22 molecules of CuSO4·5H2O (copper(II) sulfate pentahydrate), we need to calculate the molar mass of the compound and then convert it to grams.
1. Calculate the molar mass of CuSO4·5H2O:
- Copper (Cu) has a molar mass of 63.55 g/mol.
- Sulfur (S) has a molar mass of 32.07 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
- Hydrogen (H) has a molar mass of 1.01 g/mol.
- Multiply the molar mass of each element by the number of atoms present in the compound and sum them up.
- For CuSO4·5H2O, the molar mass would be:
(63.55 g/mol) + (32.07 g/mol) + (4 × 16.00 g/mol) + (10 × 1.01 g/mol) = 249.68 g/mol.
2. Convert the number of molecules to moles:
- 1*10^22 molecules represents 1 mole of CuSO4·5H2O since Avogadro's number states that 1 mole contains 6.022 * 10^23 molecules.
3. Calculate the weight of 1 mole of CuSO4·5H2O:
- Multiply the molar mass by the number of moles:
249.68 g/mol * 1 mol = 249.68 g.
Therefore, the weight of 1*10^22 molecules of CuSO4·5H2O is 249.68 grams.
Step-by-step explanation: