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Solve the equation cos4x+2sin3x−3cos2x−4sinx+2=0

User Cemal
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To solve the equation cos4x + 2sin3x - 3cos2x - 4sinx + 2 = 0, we can use trigonometric identities and algebraic manipulation.

Step 1: Rearrange the equation to isolate the trigonometric terms:

cos4x - 3cos2x + 2sin3x - 4sinx = -2

Step 2: Use the double angle formula for cosine:

2cos^2(2x) - 3cos2x + 2sin3x - 4sinx = -2

Step 3: Apply the double angle formula for sine:

2(1 - sin^2(2x)) - 3cos2x + 2sin3x - 4sinx = -2

Step 4: Expand and simplify the equation:

2 - 2sin^2(2x) - 3cos2x + 2sin3x - 4sinx = -2

Step 5: Rearrange the equation:

-2sin^2(2x) - 3cos2x + 2sin3x - 4sinx = -4

Step 6: Simplify the equation further:

-2sin^2(2x) - 3(1 - 2sin^2(x)) + 2sin(3x) - 4sin(x) = -4

Step 7: Distribute and combine like terms:

-2sin^2(2x) + 6sin^2(x) + 2sin(3x) - 4sin(x) - 3 = -4

Step 8: Rearrange the equation:

-2sin^2(2x) + 6sin^2(x) + 2sin(3x) - 4sin(x) + 1 = 0

Step 9: Factor the equation if possible. However, this equation cannot be factored further.

Step 10: Use numerical methods or technology to approximate the solutions to the equation.

Please note that due to the complexity of the equation, the solutions cannot be obtained by simple algebraic methods. Numerical methods or technology, such as a graphing calculator or computer software, can be used to find approximate solutions.

User Conan Lee
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