Answer:
410,884 units and price is 17.26 for which revenue function is maximum
Step-by-step explanation:
Given function
D= 0.25 (360−0.01p^3)^2
Revenue function
R(p) = p(0.25(360 − 0.01p^3)^2)
R′(p) = (0.25(360 −0.01p^3) ^2) + p(.5(360−0.01p^3) (−0.03p^2)) R′(p)=0
(p, f(p)) = (17.2610874799436, 410,884.335440944)
(p, f(p)) = (33.0192724889463,0)
R″ = 0.25 (0.0042p^5 − 86.4p^2)
R″ < 0, at p = 17.26
410,884 units and price is 17.26 for which revenue function is maximum