Question

Your turn Show that f(x)=x^(3)-2x-5 has a real zero between 2 and 3

Answer 1

Hi,

Explanation:

f(x) is continue since f(x) is a polynom.

f(2)=8-4-5=-1

f(3)=27-6-5=16

So there is somewhere between 2 and 3 a value of where f(x)=0 (théorème des valeurs intermédiaires)