Question

A woman has an initial lung volume of 2.75 L, which is filled with air at an atmospheric pressure of 1.01 atm. She skydives. If she increases her lung volume to 3.55 L without inhaling any additional air, what is the pressure in her lungs?

PIV₁ = P₂2V2

P₁ = first pressure
P₂ = second pressure
V₁ = first volume
Va second volume

Answer 1

Answer: 1.30 atm

Step-by-step explanation:

`(P_1)/(V_1)=(P_2)/(V_2)\\\\(1.01)/(2.75)=(P_2)/(3.55)\\\\P_2=1.30 \text{ atm}`