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One side of a rectangle is 40 ft shorter than ten times another side. Find the length of the sides, given that the area of the rectangle is 320 ft2. Enter both sides, separated by a comma.

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Answer:

8 , 40

Explanation:

The area of a rectangle is calculated by multiplying the length by the width. In this case, the area is given as 320 ft².

So, we can set up the following equation:

x * (10x - 40) = 320

Simplifying the equation:

10x^2 - 40x - 320 = 0

Dividing the equation by 10 to simplify further:

x^2 - 4x - 32 = 0

To solve this quadratic equation, we can factorize or use the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -4, and c = -32. Plugging these values into the formula:

x = (-(-4) ± √((-4)^2 - 4(1)(-32))) / (2(1))

x = (4 ± √(16 + 128)) / 2

x = (4 ± √144) / 2

x = (4 ± 12) / 2

x = (4 + 12) / 2 or x = (4 - 12) / 2

x = 16 / 2 or x = -8 / 2

x = 8 or x = -4

Since the dimensions of a rectangle cannot be negative, we discard the solution x = -4.

Therefore, the length of one side is 8 ft.

The other side can be found by substituting this value back into the expression "10x - 40":

10 * 8 - 40 = 80 - 40 = 40 ft

Therefore, the lengths of the sides of the rectangle are 8 ft and 40 ft, respectively.

User Prakhar Londhe
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