161k views
3 votes
How many molecular orbitals are needed to represent the conjugated pi system of beta-carotene?

• 1
• 10
• 11
• 20
• 22

2 Answers

5 votes

Final answer:

To represent the conjugated pi system of beta-carotene, which consists of 11 conjugated double bonds, 22 molecular orbitals are required - 11 bonding and 11 antibonding.

Step-by-step explanation:

The question asks about the number of molecular orbitals needed to represent the conjugated pi system of beta-carotene. Beta-carotene is a molecule with a chain of 11 conjugated double bonds. According to molecular orbital theory, each pi bond is made up of a pair of pi molecular orbitals - one bonding and one antibonding. Hence, for 11 double bonds, there will be 22 molecular orbitals - 11 bonding (pi) and 11 antibonding (pi*).

This means that for beta-carotene, with its extended conjugated pi system, we need 22 molecular orbitals to represent it fully.

User Oybek
by
7.4k points
3 votes

Answer:

11 becoz it is a fixed amount

User Suren Konathala
by
7.5k points