Question

Watch help video Find the 6 th term in the expansion of (4x+1)^(8) in simplest form.

Answer 1

3584x³

Explanation:

The 6th term of (4x+1)⁸ will be
`_8C_5(4x)^(8-5)(1)^5` using the binomial theorem:

`_8C_5(4x)^(8-5)(1)^5=(8!)/(5!(8-5)!)(4x)^3=(8*7*6)/(3*2*1)(64x^3)=56(64x^3)=3584x^3`