Watch help video Find the 6 th term in the expansion of (4x+1)^(8) in simplest form.

asked Dec 17, 2024 93.7k views

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3 votes

Answer:

3584x³

Explanation:

The 6th term of (4x+1)⁸ will be
_8C_5(4x)^(8-5)(1)^5 using the binomial theorem:

_8C_5(4x)^(8-5)(1)^5=(8!)/(5!(8-5)!)(4x)^3=(8*7*6)/(3*2*1)(64x^3)=56(64x^3)=3584x^3

Kaylin answered Dec 22, 2024

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