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Find the limit. Use I'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. lim

x→−[infinity]

(6x−ln(x))

User Doubleo
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1 Answer

6 votes

Answer:

Hi,

Explanation:


\displaystyle \lim_(x \to \infty) (ln(x))/(x) =\frac{\infty} {\infty} \\\\So\ we\ can\ use\ Hospital's\ rule\\\\\lim_(x \to \infty) (ln(x))/(x)=\lim_(x \to \infty)((1)/(x) )/(1) =\lim_(x \to \infty)(1)/(x) =0\\


\displaystyle \lim_(x \to \infty) (6x-ln(x))=\lim_(x \to \infty) x(6-(ln(x))/(x) )\\\\=\lim_(x \to \infty)x*6=6*\infty=\infty\\

User Yunhasnawa
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