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Use a graph below of f(x)=3e−6x2 to estimate the x-values of any critical points and inflection points of f(x). critical points (enter as a comma-separated list): x= inflection points (enter as a comma-separated list): w− Next, use derivatives to find the x-values of any critical points and inflection points exactly. critical points (enter as a comma-separated list): x= inflection points (enter as a comma-separated list): x=

User Rgisi
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Final answer:

To estimate the x-values of critical points and inflection points of the function f(x) = 3e^(-6x^2), we can analyze the graph and find that there are no critical points or inflection points. To find the x-values exactly, we need to find the first and second derivatives of the function and solve equations f'(x) = 0 and f''(x) = 0.

Step-by-step explanation:

To estimate the x-values of critical points and inflection points of the function f(x) = 3e^(-6x^2), we can analyze the graph of the function. Critical points occur where the derivative of the function is equal to zero. Inflection points occur where the second derivative changes sign. By observing the graph, we can see that there are no critical points or inflection points.

To find the x-values of critical points and inflection points exactly, we need to find the derivative and second derivative of the function. The derivative of f(x) is obtained by applying the chain rule and simplifying. The second derivative is found by differentiating the derivative of f(x).

The derivative of f(x) is f'(x) = -36xe^(-6x^2).

The second derivative of f(x) is f''(x) = -36e^(-6x^2)(1 - 12x^2).

To find the x-values of critical points, we need to solve the equation f'(x) = 0. Since the derivative doesn't have any explicit solutions, we can use numerical methods or graphing calculators to approximate the x-values.

For inflection points, we need to solve the equation f''(x) = 0. Since the second derivative is a quadratic equation, we can solve it to find the x-values exactly.

User Abenson
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