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Given that y varies jointly as x squard and z, find the constant of variation when y=225,x=3, and z=4

User Valmo
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Answer:

If y varies jointly as x^2 and z, we can write the equation as y = k * x^2 * z, where k is the constant of variation.

To find the constant of variation, we can use the given values of y, x, and z:

y = 225, x = 3, and z = 4

Substituting these values into the equation, we get:

225 = k * 3^2 * 4

225 = k * 36

Solving for k, we get:

k = 225/36

k = 6.25

Therefore, the constant of variation is 6.25.

User Dmcshehan
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