The wavelength of light emitted when the hydrogen atom undergoes the specified transition is approximately 49.972 nanometers. As for the region of the electromagnetic spectrum, this wavelength falls in the ultraviolet region.
To calculate the wavelength of light emitted when a hydrogen atom undergoes a transition from n = 234 to n = 233, you can use the Rydberg formula:
1/λ = R_H * (1/n1² - 1/n2²)
Where:
- λ is the wavelength of light.
- R_H is the Rydberg constant for hydrogen, approximately 1.097 x 10^7 m^(-1).
- n1 is the initial quantum energy level (234 in this case).
- n2 is the final quantum energy level (233 in this case).
Now, plug in the values:
1/λ = (1.097 x 10^7 m^(-1)) * (1/234² - 1/233²)
1/λ = (1.097 x 10^7 m^(-1)) * (1/(54756) - 1/(54049))
Now, calculate the difference in fractions:
1/λ = (1.097 x 10^7 m^(-1)) * (0.00001826)
1/λ ≈ 20,017.22 m^(-1)
Now, calculate the wavelength (λ):
λ = 1 / (20,017.22 m^(-1))
λ ≈ 4.9972 x 10^(-5) meters
To express this wavelength in a more convenient unit, Convert it to nanometers (nm):
λ ≈ (4.9972 x 10^(-5) meters) * (1 x 10^9 nm/meter)
λ ≈ 49.972 nm