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Converting vertex and intercept form to standard form

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Answer:

You have to simplify vertex form to convert it to standard form. The same thing applies to intercept form.

Explanation:

Vertex form: y = a(x-h)^2 + k.

Let's say a = 2, h = 3, and k = 4. (y = 2(x-3)^2 + 4)

If we expand that, we get y = 2(x^2-6x+9) + 4; this further simplifies to y = 2x^2-12x+22. Our answer is in standard form now.

Intercept form: y = a(x-p)(x-q)

Let's say a = 2, p = 3, and q = 4. (y = 2(x-3)(x-4))

All we have to do is multiply the equation out.

y = 2(x^2-7x+12); y = 2x^2 - 14x + 24. This is standard form.

Hope this helped! (its very messy)

User Zealous System
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