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1 vote
Find the perimeter of ∆ MLT

Find the perimeter of ∆ MLT-example-1
User Kriegaex
by
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1 Answer

5 votes

Answer:

we know that JKLM is a rectangle

TKL right triangle in K

Pythagore's theorem

TL²=TK²+Kl²

TL²=2²+3²

TL = V13 about 3.6m

JTM rectangle in J

TM²=JT²+JM²

TM²= 13²+3²

TM= V179 about 13.4m

we calculate the perimeter of MLT:

TL+TM+ML

3.6+13.4+15 = 32m

Explanation:

User Discodowney
by
7.3k points

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