Answer:
132gCO2
Step-by-step explanation:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
According to the chemical equation, 3 moles of carbon monoxide, CO, will react with 1 mole of ferric oxide, Fe2O3, and produce 3 moles of carbon dioxide, CO2.
To convert between moles and grams, use the molar mass of the two compounds,
For CO: M
M
=28.01 g mol
−1
For CO2
: M
M
=44.01 g mol
−1
If one mole of carbon monoxide has a mass of 28.01 g and one mole of carbon dioxide has a mass of 44.01 g, it follows that the reaction produces 44.01 g of carbon dioxide for every 28.01 g of carbon monoxide.
This is the case because of the 3:3 mole ratio that exists between the two compounds.
Therefore, 83.7 g of carbon monoxide will produce 83.7×
28.01
44.01
=132gCO2