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How many grams of iron are made when 72 grams of carbon react with excess iron (III) oxide?

User Lbottoni
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1 Answer

4 votes

Answer:

132gCO2

Step-by-step explanation:

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

According to the chemical equation, 3 moles of carbon monoxide, CO, will react with 1 mole of ferric oxide, Fe2O3, and produce 3 moles of carbon dioxide, CO2.

To convert between moles and grams, use the molar mass of the two compounds,

For CO: M

M

=28.01 g mol

−1

For CO2​

: M

M

=44.01 g mol

−1

If one mole of carbon monoxide has a mass of 28.01 g and one mole of carbon dioxide has a mass of 44.01 g, it follows that the reaction produces 44.01 g of carbon dioxide for every 28.01 g of carbon monoxide.

This is the case because of the 3:3 mole ratio that exists between the two compounds.

Therefore, 83.7 g of carbon monoxide will produce 83.7×

28.01

44.01

=132gCO2

User Gopakumar N G
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