Final answer:
To test the claim of bias in grand jury duty selection, we set up a hypothesis test. The test statistic is calculated using the z-score for proportions, and the resulting P-value is compared to the significance level to determine if we should reject the null hypothesis.
Step-by-step explanation:
To address the claim that the selection process for grand jury duty is biased against a particular ethnicity, we will conduct a hypothesis test using a normal distribution as an approximation to the binomial distribution because of the large sample size.
Hypotheses
The null hypothesis (H0): The selection process is fair, and the proportion of the selected jurors of the ethnicity in question is equal to the proportion in the population eligible for jury duty (p = 0.792).
The alternative hypothesis (Ha): The selection process is biased against the ethnicity, implying the proportion of selected jurors of the ethnicity is less than the proportion in the population (p < 0.792).
Test Statistic
To calculate the test statistic, we use the formula for the z-score in a proportion test:
z = (p-hat - p) / sqrt(p(1-p)/n), where p-hat is the sample proportion, p is the population proportion, and n is the sample size.
Thus, the test statistic is z = (0.39 - 0.792) / sqrt(0.792(1-0.792)/888), which should be calculated and rounded to two decimal places.
P-value
The P-value can be found by looking up the calculated z-score in a z-table or using a statistical software. It should be compared to the significance level (alpha = 0.01).
Conclusion
If the P-value is less than the significance level, we reject the null hypothesis, indicating evidence of bias. If the P-value is greater, we fail to reject the null hypothesis, indicating insufficient evidence of bias.