Question

AMDM.PR.6.3 (HC)

Mark saw a flier for a bakery that said 1 in 4 Easter eggs will contain a
prize. If Mark buys 6 Easter eggs, what is the probability that he will
get exactly 2 prizes?
O 0.10
0.30
0.002
O0.50

Answer 1

Answer: 0.30

Explanation:

First, find the total number of ways Mark can get two prizes from the six eggs. This is the same as choosing two eggs out of six to have prizes, which can be calculated using the formula for combinations: 6 choose 2 = 6! / (2! * (6-2)!) = 15. So, there are 15 different ways Mark can get two prizes from the six eggs.

Next, find the probability of each of these 15 ways happening. Since the probability of getting a prize in one egg is 1/4, and the probability of not getting a prize in one egg is 3/4, the probability of getting exactly two prizes in six eggs is (1/4)^2 * (3/4)^4 which equals 0.1975.

Finally, multiply the number of ways Mark can get two prizes by the probability of each way happening to get the total probability: 15 * 0.1975 = 2.9625. So, the exact probability of Mark getting exactly two prizes from the six Easter eggs he buys is 0.29625, or about 29.63%. Rounding, we get the answer of 0.30.