Final answer:
Cr2O72-(aq) predominates in acidic conditions where additional H+ ions shift the equilibrium right, resulting in an orange color. The reaction is not a redox reaction, as there is no change in oxidation states. Adding sulfuric acid results in an orange color, whereas adding NaOH results in a yellow color, visually demonstrating dynamic equilibrium.
Step-by-step explanation:
Conditions for Predominance of Cr2O72-(aq)
To determine under what conditions Cr2O72-(aq) will predominate, we can refer to the equilibrium:
CrO42-(aq) + 2H+ (aq) <--> Cr2O72-(aq) + H2O(l).
Cr2O72-(aq) will predominate in acidic conditions because an increase in H+ ions shifts the equilibrium to the right, in accordance with Le Chatelier's Principle.
Is This a Redox Reaction?
This is not a redox reaction because there is no change in the oxidation states of the elements involved. Both species contain chromium in the same oxidation state, -2 for oxygen and +6 for chromium.
Effects of Adding Sulfuric Acid (H2SO4)
Adding sulfuric acid to the solution will introduce more H+ ions, shifting the equilibrium to the right to form more Cr2O72-(aq), resulting in an observable color change from yellow to orange.
Effects of Adding Sodium Hydroxide (NaOH)
The addition of sodium hydroxide (NaOH) will remove H+ ions from the system through the reaction H+ + OH- -> H2O. This decreases the concentration of H+, shifting the equilibrium to the left and making more CrO42-(aq), causing a color change from orange to yellow.
Demonstrating Dynamic Equilibrium
To demonstrate that equilibrium is a dynamic process, an experiment can be conducted by adding a reactant or a product and observing the system's response to maintain equilibrium. For example, adding sulfuric acid to the equilibrium mixture of CrO42-(aq) and Cr2O72-(aq) and observing the color change demonstrates the shifting of equilibrium to counteract the change in concentration.