Answer:
B. 7.65 m/s^2 (R)
Step-by-step explanation:
We can use Newton's second law to find the acceleration of the system. The force acting on the system is the force of gravity acting on the masses, and the force of friction acting on mass 2. The force of friction is equal to the coefficient of kinetic friction multiplied by the normal force, which is the force of gravity acting on mass 2.
Therefore, the force of friction is (1.1 kg)(9.81 m/s^2)(0.11) = 1.20 N. The net force acting on the system is the force of gravity minus the force of friction, which is (1.80 kg + 1.10 kg + 3.30 kg)(9.81 m/s^2) - 1.20 N = 43.5 N. Finally, we can use Newton's second law to find the acceleration of the system, which is a = F_net / (m1 + m2 + m3) = 43.5 N / (1.80 kg + 1.10 kg + 3.30 kg) = 7.65 m/s^2. Therefore, the answer is B. 7.65 m/s^2 (R)