The center of mass for the given rod is ≈ 29.68 cm from the left end.
How to determine the center of mass for the given rod?
Given the rod with distinct sections:
1. Iron Section:
Length (L1) =

Density (ρ1) =

Mass (m1) =

2. Aluminum Section:
Length (L2) =

Density (ρ2) =

Mass (m2) =

3. Total Mass (M):

4. Center of Mass (x):
The center of mass is denoted by considering the weighted positions of each section:
x1: Distance from the left end to the center of mass of the iron section (x1 = L1/2 = 18 cm)
x2: Distance from the left end to the center of mass of the aluminum section (x2 = L1 + L2/2 = 80 cm)
Using the formula:

Substituting the values:

Hence, the center of mass for the given rod is approximately 29.68 cm from the left end.