Question

A meter thick with a mass of 0.63 kg is held perpendicular to a vertical wall by a cord of length of 1.8m attached to the end of the meter stic and also to the wall above uther end of the meter stick

(a) Determine the tension in the cord.

Answer 1

The tension in the cord is 6.174 N.

Step-by-step explanation:

To determine the tension in the cord, we need to consider the equilibrium of forces acting on the meter stick. Since the meter stick is held perpendicular to the vertical wall, the weight of the meter stick can be considered as acting at its center of mass. The tension in the cord must balance the weight of the meter stick to keep it in equilibrium. The tension in the cord can be calculated using the equation:

Tension = Weight of the meter stick

Weight of the meter stick = Mass of the meter stick × acceleration due to gravity = 0.63 kg × 9.8 m/s²

Therefore, the tension in the cord is 6.174 N.

Answer 2

Due to missing details such as the angle of the cord with respect to the wall or horizontal plane, it's not possible to determine the tension in the cord accurately without additional information.

Step-by-step explanation:

The question seems to involve finding the tension in a cord that is holding a meter stick against a wall. Due to some confusion in the original problem statement, I'm assuming the meter stick is held horizontally, with the cord attached at one end of the stick and connected to the wall above. To find the tension in the cord, we would consider forces such as the weight of the meter stick and the angle formed by the cord with respect to the horizontal.

However, the question is not completely clear, and essential details like the angle between the cord and the wall are missing, making it impossible to provide an accurate answer. In a well-defined problem, the tension can be calculated using the principles of equilibrium, where the tension must counteract the torque caused by the weight of the meter stick acting at its center of mass.